#include <time.h>
#include <stdio.h>
#include <stdlib.h>

#define __ "Y\n : ! ,.?>"
#define D(f) ; } int f(int i) { return
#define E(a,b,c,d,e) b##d,c,e,a
#define e(a,b,c,d) a##b##c##d
#define B *p++ - ' ' || !p++
#define _(k) o(*#k - 64)
#define G(g,l,k,o,e,d,n,c,i,b,a,f,j,m,p) \
a#b#c#d#e#f#g#a#i#j#k#l#m#n#o e,i l##c,m##b; d g j n h(k 30:1); o p f}

			G(E(f ( 9) -s
				? -s + 'q'
				? f( 5 ) -s &&'d' -
			       s?U(  3 ) ||_(J)
				:A ( s- f( 5 ))
				:(c= 4 *
			      4):

	g(0)D(

		V)c <= 3 *4 + 3&&c && V(X ( i) ) ;
	}

	int , time ( 0)& , c - 15 || P

	(1

):0,
	& ( !!d	    ( 0 )
	  ||(a=! _(S)) ,b= 0 )||
	a
		?d(a  = 0)
			? _
(I):			w ( j =!W(j=_ (V ))) ,

				l(_
				    (Y+ s ) )
				  )e

	(
	main(){;
	    ;;;s , ra,
	 n, d), && C ( j +R( s-j+t( i- 1) )
		   )D( W)m[ c* 4| z( j ) ]
	    &&_( X )E (d	   ( 0
		       )&&  R( 6)/ 6
			   ? c= 17|_ ( T )
			   :01,||+
			       , v =i & 3 ^ 2
			       ,+j & 3&&W ( j)||y ( 10 )D (k) --
				   j ? k ( O[j]=R(15 ))
: 1 D
			 ( H )o ( 7+! !  i+3 )+

				  i?

    c=i /4 & 63,
    a= 1

:0)

    D ( f )( p =M ,q ( i),*p+86)
    D ( l) * f, B?

			   B ?B ?B? B ?B ?B
		 ?7 :B?B ?36: 59 * 89 *5 * 2 :B?6587
	     *77 :9 + 2:B ?B?B?9: 5 : 37 : B ? 5 +5:4:20:
			       B?B?B?32

		  :e( 4, 3 , 1 *4 * 59  * 1 , 7):B?
			       17: 34 : 19 :B ?
				      8 *2 :B ?
				      2:26: B?
				       B?B ?B ?

	82 *+ 576: B ?33 :22  :5 * 5:3 *4 :3:B ?B ?B? B ?6 +
	+ 17 : B?B?13:6 : 9 *2:B?15 : 7 *2 :

				 B ?
				 B ?
			    27:24: 31 : B?


		  B? +  29 :,
		  m [a^ 2  ] =T( 8 * 7) ;j= 3
		      ;
		    ;
	      Q, ;int
	       P ( int
		  i )

      {time_t(x )				=+ 0+
	time(0) ;                       j=E( u (i  ) : i D(R )e(r ,
      a ,n ,d) ()% i+1,                 ( e( l  , o,
      caltim , e ) (& x))     ->e(          tm_h , o, u  , r)
	;retur ,				i?_( W
):	_( U) D(Y)			  *p&&  *p<3 * 11 ?
	  ( ++ p ),				  n j= + 34  +( j< 6
							||j>19 ),Y (i)
: *p

    D ( F)	i == 9  ?1 :
	F(	(i+ 7)% ( 7 +  3) ) +!O[ i
   ]D(u)	*p &&* p -32? p ++)
    D (h  )	i ?*++*S=i%  ( 38)- 1,
    D ( A )!    n?i&&!g ( (0  ) ) ||K (  j=4| ! !i ) :  N(!i )D(
                Q)++j<

	       (s )  &&Q ( t( i)^i )
    D( U	)i>= 0 ?U( i- 1 )||~f (i+1 ) == ~  s
				      &&H (m[c* 4 |z(i)] )
:0;D


		( X) + b && b<, for (*S = M  ; *
p; ),

		gets ( L, + 98 , stdin ) ?
		   p= L, E (r( 0 ): 0 ,h( i /  38 ) : 0;D( C)!
		   ( m[j]+m [a= i] ) ?m[j[m]= i]=j:0;D (d) !
			  b+(*  O-
			   c)*
			     *  O; D (z )


					      -~- ~ -~i +
	v
		& 3 D(y)( putchar ) ( i)
    D ( q )	i& ,!(O[j = i]
		 || _ ( O))+a :0;
    D (w)O[	j] ==c && o

	(( !i ++ ? ! !_ (M

):

	0) +15)|| ++ j<9 &&w (
i)D	( r )*p?			*p -4?
					* p -6 ?
				     y(*p <9 + 2?__[
					    * p
]:			 * p+ 7 +79):o( j+1) : o (26+j),&q ( -!
		  * p ++ + i )D(x)i? a=x ( ( -- i)), ++ p )
	    D( t ) i,   | C((j=i*
       T(i-4 ))  +R
    (3 ) + 4 )
   D(J) !j                                --E( 0 D  ( K )!-!N, || i &,
                                                _( R ) :i* c== (O
   [ j ] )				&&n==f (j+   6  +    5   * 4)?O
    [j]=			   !i *    c-_   (    L)    :J(i )
    D ( N )			j=9, & d(0 )? j= 6 | ! i , J(i )D 
			( o)(*S = p , ++ S,p = M , r (q (i) ),-- S,  p = *S))
		    ( (l (_ (Q )),n =s,i ^5 ) ) ;, E(j ,
		sign ,  v ,ed ( b ) ;;
	      int   c =1 ,O[9])
            ;int(  s
)=
	 E (n ;char, 1 ,a,6 ,o ())*  Z[
	E(M [37 * 9 *3 ] ,0,L [ 99] ,3] , * *S=Z ) ;
	 E (*p=+1 ,char( m)[6 , co , 4 ],ol)
				  +,
	   V ( v=*O = k( j= 9 )) ;
	return ! c&& - ~ ~ - -! printf
	 ( ( "%d \n") , F (P ( 0) +6)            *50 + !  ! b*
	  ( +b - (int)time ( 0 )) )
;, (         b= 60 + time ( 0)+ 60 * 4)              ;, n =Y
              (u (s =Y (i) ) )

	:  (exit(                                      0)
	,i)D( g )x (  _(N) ^ 9)? !( a =0) : _  ( P )D (T)!  i|,
	(2); s=35; Q(3);

	s=59; Q(6);


	a=1;




    )